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 Infosys  |  Question 27 of 46    Print  
The colors on the two sides were
different and no two cards had the same color combination. When
the cards were distributed to them, they kept their cards on the
table with one side per card facing up, of course. Each cardholder
knew the color of the hidden side of his card. They spoke up one
by one as follows:
A: My card, showing Red above,
has either Green or Blue color beneath
B: My card, showing Green above,
has neither Green nor Blue color
beneath
C: My card, showing Yellow above,
has either Blue or Yellow color
beneath
D: My card, showing Blue above,
has either Blue or Yellow color beneath
However, later it was found that
exactly two of them were lying. Can you find who
was lying and what were the colors
on the hidden sides of each card?


Wht is the correct answer & pls mention the solving procedure.

  
Total Answers and Comments: 2 Last Update: June 17, 2006     Asked by: Archiman Ganguli 
  
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June 13, 2006 09:28:06   #1  
barani        

RE: The colors on the two sides weredifferent an...
C and D can lie as same colour is not possible on both sides and the other possibility makes their cards having same colour combination of blue and yellow. the possibility isA red -blueB green-yellowC yellow-redD blue-green
 
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June 16, 2006 22:40:05   #2  
Prathyusha        

RE: The colors on the two sides weredifferent an...

The answer for this question is of Course there is a chance for C and D to lie since there cannot be 2 colors same on either side of the card.So C and D lie.

The possible combination for all of them is as follows:

A  red - blue

B  green - yellow

C  Yellow - red

D  blue - green

Let us think that no color repeats.If that is the case the answer would probably be the right answer.


 
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