CTS - A and B r fighting .B fires 3 times as many missiles as A. Total hits: total misses = 1/7 .B’s misse

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A and B r fighting .B fires 3 times as many missiles as A. Total hits: total misses = 1/7 .B’s misses 357.B’s hits – A’s hits = 66.A’s hits?

Total Answers and Comments: 3

Last Update: February 11, 2008 Asked by: suma

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December 01, 2006 04:16:38

Raghavan

RE: A and B r fighting .B fires 3 times as many missil...

very simple

b's miss - 357

b hits - a hits 66

hits : misses 1/7

h/m of b 1/7

solving we will get b hits as 51

putting in the equation we will get the answer as 51+66 117 missliles

so a hits are 117 misslies

bechara b......

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January 30, 2008 11:19:47

suman123_456

Member Since: December 2007 Contribution: 2

RE: A and B r fighting .B fires 3 times as many missiles as A. Total hits: total misses = 1/7 .B’s misses 357.B’s hits – A’s hits = 66.A’s hits?

is answer 142?????/ plz reply

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February 11, 2008 03:04:04

junaed_ahmed

Member Since: January 2008 Contribution: 2

RE: A and B r fighting .B fires 3 times as many missiles as A. Total hits: total misses = 1/7 .B’s misses 357.B’s hits – A’s hits = 66.A’s hits?

i think there is some wrong data in the question because its coming in fraction and if i am wrong then please post the correct solution

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