A can swim & cross 50m(the length of swimming pool) in 2 min. B can swim & cross 50m in 2min 15sec. Every time when they meet a bell gong is struck. For 2000m how many bell sounds might be produced?

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Vikrant

  • Apr 6th, 2006
 

I think 38

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sharath

  • Jun 26th, 2006
 

exactly 35 gongs

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mani

  • Jun 30th, 2006
 

can anyone expalin the answer pls......

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hari

  • Nov 16th, 2006
 

2000/50m=40times they crossed the pool

while travelling 4 times a will cross in the pool in 8  min

and b can travel in 9 min 

so for 40 times it is 36 

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Deepak

  • Apr 24th, 2007
 

series of distance covered at time when gong rings is

53+106+159..........+(last term <2000)

now the last term is given by hit and trial method taking the max no. of terms in the series as 40

tn== 53+(40-1) *53=2120 it is not possible
similarly not for 39,38
but for 37

tn== 53+(37-1) *53=1961 it is possible
hence the answer is 37

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Sourabh Bhawsar

  • Nov 19th, 2011
 

the answer will be 35.
because in every loop the difference produce between this two is 6.25 meters.
so there are 2000/50= 40 loops.
so there total difference produce will be 40*6.25 = 250 meters.
jst subtract this from total 2000 - 250 = 1750
hence the bell sound produced = 1750 / 50 = 35. (answer)

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