There is a string 120000 12 0 .125 , how you will find the position of the decimal place?

INSTR('120000 12 0 .125',1,'.')
output 13

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Phani Josyula

  • Aug 30th, 2005
 

INSTR('120000 12 0 .125',1,'.') is the right way of params.

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