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A + B + C +D = D + E + F + G = G + H + I =17.

IF A = 4 WHAT ARE THE VALUES OF D AND G. EACH

LETTER TAKEN ONLY ONE OF THE DIGIT FROM 1 TO 9.

8MARKS


  
Total Answers and Comments: 6 Last Update: June 19, 2006     Asked by: Lakshmanan 
  
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February 19, 2006 23:35:48   #1  
rajesh        

RE: A + B + C +D = D + E + F + G = G + H + I =17.

4+9+3+1 1+7+8+1

so d & G is 1 only


 
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February 22, 2006 07:20:05   #2  
Nidhi        

RE: A + B + C +D = D + E + F + G = G + H + I =17.

D 5

G 1

This has been derived as

2 + 4 + 6 + 5 5 + 3 + 8 + 1 1 + 7 + 9


 
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February 28, 2006 04:16:51   #3  
Dhinakar        

RE: A + B + C +D = D + E + F + G = G + H + I =17.
d 9 and G 4.because 4+3+1+9 9+1+3+4 4+1+7+6 17
 
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June 05, 2006 09:38:21   #4  
Nitin Sahdev        

RE: A + B + C +D = D + E + F + G = G + H + I =17.
I think as per the question we have to use each number between 1 and 9 exactly once only.so as far as i think the answer to this puzzle will be4+6+2+5 + 8 + 3 + 1+7+9so D would be 5 and G would be 1Cheers!!!!
 
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June 06, 2006 02:51:09   #5  
Maria        

RE: A + B + C +D = D + E + F + G = G + H + I =17.

Hai

I am Maria Kindly send me logical steps to get this ans.

Regards

Maria


 
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June 19, 2006 02:13:10   #6  
db        

RE: A + B + C +D = D + E + F + G = G + H + I =17.

hi maria

listen to the song un dos tres by ricky martin and u will find the answer of D and G to be equal to mean of 1+2+3

if u still have doubt then listen to ek do teen from the movie tezaab.

regards

db


 
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