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A contribution of Rs. 500 was raisedfrom 500 people. The fee was as follows:
Men: Rs.3.00 each
Women: Rs. 2.00 each
Childern: 0.48 each
If number of women is more than number of men, how many childern are there?

two equations are
3x+2y+0.48z=500
x+y+z=500
solving we get
y=(6500-63x)/38 under y>x
very difficult to solve
give alternative way




  
Total Answers and Comments: 2 Last Update: April 04, 2006     Asked by: pankaj_ismd 
  
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February 25, 2006 15:38:44   #1  
abhishek_adhikari Member Since: February 2006   Contribution: 1    

RE: A contribution of Rs. 500 was raisedfrom 500 peop...
hit and trail method
 
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April 04, 2006 05:41:13   #2  
Rathi Member Since: April 2006   Contribution: 1    

RE: A contribution of Rs. 500 was raisedfrom 500 peop...

solution:

let no of men as m women as w and children as c.

3m+2w+0.48c 500 ----- I equation

m+w+c 500 -------II equation

solve I and II get

1.52c 500+m put least possible values for c and m so that condition satisfy

try c 350 and m 32.

use this values in equ II get w 118.

now check ur equ I it will satisfy.

Therefore ans is men 32 women 118 children 350.


 
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