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If a die is marked according like that 1-6, 2-5,3-4 comes apposite to each
other, what is the number of combination that a die can be marked?

  
Total Answers and Comments: 4 Last Update: May 13, 2006     Asked by: sambath 
  
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January 31, 2006 07:21:54   #1  
Harry        

RE: If a die is marked according like that 1-6, 2-5,3-...

at first to place 1 we have 6 choices. then to place 6 only one .

later to place 2 we have 4 choices and to place 5 only one.

finally to place 3 we have 2 choices and to place 4 only one.

so total chances to arange them is 6*1*4*1*2*1 48.


 
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March 02, 2006 21:07:42   #2  
G@0        

RE: If a die is marked according like that 1-6, 2-5,3-...

In fact I think there's only 2 combinations.

Plz remember a die is 3D symmetric that makes it tricky.


 
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April 05, 2006 07:20:58   #3  
Rajiv        

RE: If a die is marked according like that 1-6, 2-5,3-...

Hi

Can you please elaborate how did u come to this conclusion that there are only 2 ways to arrange the combinations of 1-6 2-5 3-4


 
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May 13, 2006 06:43:05   #4  
Sravya        

RE: If a die is marked according like that 1-6, 2-5,3-...
Hi all The answer should be 7. As specified in the question one combination is 1-6 2-5 and 3-4. Now fixing 1-6 the possible different combinations are 1-6 2-3 4-5 and 1-6 2-4 3-5 Now fixing 2-5 the possible different combinations are 2-5 1-3 4-6 and 2-5 1-4 2-6 Now fixing 3-4 the possible different combinations are 3-4 1-2 6-5 and 3-4 1-5 6-2. Since for a dice have 1-6 in opposite is same as having 6-1. Hope its clearThanks Sravya:)
 
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