Motorboat A leaves shore P as B leaves Q; they move across the lake at a constant speed. They meet first time 600 yards from P. Each returns from the opposite shore without halting, and they meet 200 yards from Q. How long is the lake? this question has 1600 or 1000 as ans . bt i really dont know the approach.so could somebody plz tell me

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Dec 6th, 2005
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Himanshu

Dec 7th, 2005

p-----------x-----------q
a-->                        <--b
<--600--><---(x-600)--->
<---(x-200)---><--200-->
let speed of a and b are a and b kmph resp. and distance b/w pq is x.
if a covers the distance of 600 in 't' hours and b covers x-600 at same time.
so 600/a=(x-600)/b    ------eq.1
again they meet when a is 200 from q that means a covers the distance of (x-600)+200 and at same b covers (600)+(x-200)
so {(x-600)+200}/a={(600)+(x-200)}/b    --------eq.2
solve 1 and 2 u'll get x=1600,0 obviously 1600 is the answer
i think this will help u