Pavan_paladin

 Profile Answers by Pavan_paladin 

• Nov 16th, 2005

 

20,10

Chitra

• Nov 21st, 2005

 

The ship is twice as old as its boiler was when the ship was as old as the boiler is now.And the combined age of the ship and the boiler is 30yrs.
What is the age of the ship and the boiler?

Pravin Vaidya

• Nov 22nd, 2005

 

At present

Age of ship=x

Age of Boiler=y

Therefore  x+y=30 ----------(1)

when x was as old as y i.e (x-y) years before

(x-(x-y))=(1/2)*(y-(x-y))

which is equal to

3y-2x=1 ----(2)

solving (1)  and  (2)

we get

x=18 and y=12  (Present age)

pravin_vaidya

 Profile Answers by pravin_vaidya 

• Nov 22nd, 2005

 

ship=18 Boiler =12

saba

• Jan 3rd, 2006

 

ship age is x(present age).

boiler age is y(present age).

when x was as old as y i.e (x-y) years before

(x-(x-y))=2*(y-(x-y))

which is equal to

3y-2x=0 ----(2)

solving (1)  and  (2)

we get

x=18 and y=12  (Present age)

Manmeet

• Jun 19th, 2006

 

Let the age of ship be x yrs, and that of boiler be y yrs

x+y=30

when ship was as old as boiler is now, means x-y yrs before, the present age of ship is twice the age of boiler at this time,

thus, boiler's age is y-(y-x)

therefore, x=2(y-(y-x))

on solving, 4y=3x

as x+y=30,

y=90/y and x=120/7

sunnyparag

 Profile Answers by sunnyparag 

• Dec 5th, 2007

 

ships age be ->s,Boilers age be ->b
s+b=30......condition 2
s=2(b-(s-b))...condition 1
therefore 3s=4b
solve the above equations to get the final value i.e. s=120/7yrs,b=90/7yrs

antonymraphel

 Profile Answers by antonymraphel 

• Dec 8th, 2007

 

 age of ship=x
 age of boiler=y
 given
x+y=30

know tat x=2y

from these two expression
3y=30
y=10 = age of the boiler

since age of the ship 9x0=2*age of the boiler
x=2*10
x=20