Analytical - there are 1/5th behind me in a race and 5/6 before me .can u tell how many participated in the race

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there are 1/5th behind me in a race and 5/6 before me .can u tell how many participated in the race

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Total Answers and Comments: 9

Last Update: November 26, 2005 Asked by: naga

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October 06, 2005 07:13:54

baskar

RE: there are 1/5th behind me in a race and 5/6 before...

n(1-1/5)+n(1-5/6) n find n

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October 23, 2005 02:15:14

ankurmiddha

RE: there are 1/5th behind me in a race and 5/6 before...

ans - 32

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October 26, 2005 09:52:27

devakumar

RE: there are 1/5th behind me in a race and 5/6 before...

(5x/6+x/5)+1 x(25x/30+6x/30)+1 x(31x/30)+1 x(31x+30)/30 xthere fore 31x+30 30xx 30

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October 31, 2005 05:25:46

krishnamraju

Member Since: October 2005 Contribution: 7

RE: there are 1/5th behind me in a race and 5/6 before...

5/6x+1/5x 1+x;x 30;

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November 04, 2005 05:28:42

krishnamraju

Member Since: October 2005 Contribution: 7

RE: there are 1/5th behind me in a race and 5/6 before...

(x-1)1/5+(x-1)5/6 x+1;x 31;

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November 04, 2005 05:39:22

krishnamraju

Member Since: October 2005 Contribution: 7

RE: there are 1/5th behind me in a race and 5/6 before...

Krishnam Raju Wrote:(x-1)1/5+(x-1)5/6 x+1;x 31;The previous one might be the wrong answer..sorry for that...

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November 22, 2005 05:41:14

Somnath Paramanick

RE: there are 1/5th behind me in a race and 5/6 before...

Let us assume there are x number of racers excluding the person.

Therefore by the problem we have

(1/5)x+(5/6)x x+1

or 31/30 x x+1

or x 30

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November 22, 2005 06:48:49

virendra

Member Since: November 2005 Contribution: 1

RE: there are 1/5th behind me in a race and 5/6 before...

31 cyclists

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November 26, 2005 11:22:11

sharad vasisht

RE: there are 1/5th behind me in a race and 5/6 before...

Ans. 13

(x-1)/5+ 5/6(x-1) x where x is total no.

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