satheesh

• Sep 19th, 2005

 

U can't get inputs as different datatypes u can get them as String only after getting them u can convert them using the Integer.parseInt() same for float .For char u better use a for loop and get string character by character and store iti in array.use charAt() method

Devidas Sonawane

• Oct 27th, 2005

 

By using StringReader we access parameter as String and by type-casting  into it into (Integer.parseInt(variable_name)) int, float, char, double, long etc. U don't get parameter as primitive type use Wrapper classes.

Devidas Sonawane

• Oct 27th, 2005

 

By using BufferedReader we access parameter as String and by type-casting  into it into (Integer.parseInt(variable_name)) int, float, char, double, long etc. U don't get parameter as primitive type use Wrapper classes

Bharathi

• Jun 27th, 2006

 

You can take input parameters using System.in() method for all premitive datatypes.

sanjeeb

• May 21st, 2007

 

Can you say how to take input parameters of any primitive type using System.in() method by giving some examples.

geeksterrahul

 Profile Answers by geeksterrahul 

• Jul 24th, 2009

 

Firstly take the User input as String using the BufferedReader API.Call br.readLine();

Once you get the input Use .ValueOf method for conversion.

 

Eg:

String MyString;

BufferedReader br = ............;

MyString = br.readLine();

Integer INTVALUE = Integer.ValueOf(MyString);

dinesh

• Oct 12th, 2011

 

example we get input for integer,
Scanner scan = new Scanner(System.in);
int variable_name = scan.nextInt();