There are three different boxes A, B and C. Difference between weights of A and B is 3 kgs. And between B and C is 5 kgs. Then what is the maximum sum of the differences of all possible combinations when two boxes are taken each time.

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Meghraj Shah

  • Sep 5th, 2005
 

the maximum weight differance between 2 boxes taken in all combinations is 8kg+5kgs+3kgs

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SUBRAHMANYAM

  • Dec 26th, 2005
 

A-B=3KG,

B-C=5KG

A-C=8KG,

COMBINATION OF B-C AND A-C WILL GIVE MAX WEIGHT i.e. 13KG.

Arvinder

  • Apr 4th, 2006
 

Total Diff. is 16Kgs (8Kg+5Kg+3Kg)

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dheepti

  • Sep 15th, 2006
 

A-B = 3

B-c = 5

a-c = 8

so sum of diff = 8+3+5 = 16 kgs

niharika

  • Apr 4th, 2007
 

13 is the right answer as the question is max of sum when 2 combinations of boxes are drawn

pooja

  • May 10th, 2007
 

the ans is 8+3+5=16

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shilpa

  • Jun 10th, 2007
 

13 is the right answer because we havE to consider the max sum  of diff with 2 combinations so its
B-C? AND A-C ? 'S SUM
?5? +? 8? = 13?

case i   : A=x kgs B=(x+3) kgs C=(x+8)kgs  then S.O.D = 16kgs
case ii  : A=x+3 B=x C=x+5 , S.O.D=10kgs
case iii : A=x+8 B=x+5 C=x ,S.O.D=16kgs
altogether 42kgs

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