Narmadeshwra Jha
Answered On : Aug 25th, 2005
the answer is
5/(n+5)
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MAHAVEER PATIL
Answered On : Feb 3rd, 2006
0.462
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=(5/6)*(6/7)*(7/8)*...((n+3)/(n+4))*((n+4)/(n+5))
=5/n+5
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5/6*6/7*7/8*8/9--------------n+3/n+4*n+4/n+5 all the terms cancel out each other and remainder will be ans ----- 5/n+5
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Bhuvan Bhoot
Answered On : Jul 16th, 2006
5/(5+n)
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5/(n+5)
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YOGENDRA GUJAR
Answered On : Feb 3rd, 2007
leaving the first numerater and last denominater, all the numerater and denominater will cancelled out one another. Ans. 5/(n+5)
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5/(n+5)
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5/(n+5)
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its 5/(n+5)
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5(n+4)/(n+5)
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the answer is 5/(n+5)
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1-1/6=5/6;1-1/7=6/7;........(1-(1/n+4))=(n+3)/(n+4);(1-(1/n+5))=(n+4)/(n+5);
there fore
(5/6)(6/7)........((n+3)/(n+4))((n+4)/(n+5))=5/(n+5)=1-(n/(n+5))
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5/n+5
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5/(n+5)
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its ans is 1
one term num eqal second term deno
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5/(n+5)
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n(n+5)
other terms cancelled by each other.
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5*(1/n+5)
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5/(n+5)
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5/n+5
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5/n+5
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5/(n+5)
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The answer is 5/n+5.
Since everything gets cancelled.
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1/(n+5)
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5/n+5
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Take n=5 for example, then above equation becomes 5/6*6/7*7/8*8/9*9/10=5/10.
Which implies all the term cancel except first numerator and last denominator, so in general 5/n+5
is the answer.
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5/n-1
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Sapna
Answered On : Apr 16th, 2012
The answer is zero because expression is (1-1/6)(1-1/7)........ 1-1=0 and 1-1/6=0 so (1-1/6)*(1-1/7).....=0
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