Aptitude - (1- 1/6) (1-1/7).... (1- (1/ (n+4))) (1-(1/ (n+5))) = ?

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(1- 1/6) (1-1/7).... (1- (1/ (n+4))) (1-(1/ (n+5))) = ?

Total Answers and Comments: 10

Last Update: May 27, 2008

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August 25, 2005 04:56:14

Narmadeshwra Jha

RE: (1- 1/6) (1-1/7).... (1- (1/ (n+4))) (1-(1/ (n+5))) = ?

the answer is

5/(n+5)

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February 03, 2006 11:40:08

MAHAVEER PATIL

RE: (1- 1/6) (1-1/7).... (1- (1/ (n+4))) (1-(1/ (n+5)...

0.462

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February 21, 2006 12:35:45

anbarasigopu

Member Since: February 2006 Contribution: 16

RE: (1- 1/6) (1-1/7).... (1- (1/ (n+4))) (1-(1/ (n+5)...

=(5/6)*(6/7)*(7/8)*...((n+3)/(n+4))*((n+4)/(n+5))

=5/n+5

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July 10, 2006 15:50:15

gettopooja

Member Since: July 2006 Contribution: 5

RE: (1- 1/6) (1-1/7).... (1- (1/ (n+4))) (1-(1/ (n+5)...

5/6*6/7*7/8*8/9--------------n+3/n+4*n+4/n+5 all the terms cancel out each other and remainder will be ans ----- 5/n+5

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July 16, 2006 13:18:56

Bhuvan Bhoot

RE: (1- 1/6) (1-1/7).... (1- (1/ (n+4))) (1-(1/ (n+5)...

5/(5+n)

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July 17, 2006 14:46:20

bhuvanbhoot

Member Since: July 2006 Contribution: 7

RE: (1- 1/6) (1-1/7).... (1- (1/ (n+4))) (1-(1/ (n+5)...

5/(n+5)

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February 03, 2007 07:49:34

YOGENDRA GUJAR

RE: (1- 1/6) (1-1/7).... (1- (1/ (n+4))) (1-(1/ (n+5)...

leaving the first numerater and last denominater, all the numerater and denominater will cancelled out one another. Ans. 5/(n+5)

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May 18, 2008 18:57:33

sarat_619

Member Since: May 2008 Contribution: 6

RE: (1- 1/6) (1-1/7).... (1- (1/ (n+4))) (1-(1/ (n+5))) = ?

5/(n+5)

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May 21, 2008 01:21:05

dinesh_sun7

Member Since: May 2008 Contribution: 4

RE: (1- 1/6) (1-1/7).... (1- (1/ (n+4))) (1-(1/ (n+5))) = ?

5/(n+5)

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May 27, 2008 00:12:50

#10

akshaygs21

Member Since: May 2008 Contribution: 7

RE: (1- 1/6) (1-1/7).... (1- (1/ (n+4))) (1-(1/ (n+5))) = ?

its 5/(n+5)

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