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I2 Technologies Placement Papers
 

PLease post any I2 Technologies Placement Papers in the comments section.

PART 1:
THERE ARE 20 MULTIPLE CHOICE QUESTIONS .EACH QUESTION CARRIES 3
MARKS.THERE IS NEGATIVE MARKING FOR EACH WRONG ANSWER
MINUS 1 MARK.HERE ARE SOME QUESTIONS OF THIS PART.

1. convert 0.9375 to binary (c)
a) 0.0111 b)0.1011 c)0.1111 d)none

2.( 1a00 * 10b )/ 1010 = 100 (b)
a) a=0,b=0 b)a=0, b=1 c) d)none

3. in 32 bit memory machine 24 bits for mantissa and 8 bits for
exponent. to increase the range of floating point.
a) more than 32 bit is to be there.
b) increase 1 bit for mantissa and decrease 1 bit for exponent
c) increase 1 bit for exponent and decrease one bit for mantissa
d)

4. this on logical gates

A---------------------------------- OR -------
| | |
|------- not ----- | |-- AND --- X
| | |
|---- AND ------ |
| |
| |
| |
|---------- |
| |
B----------------- NOT -------------------------

X = ?
a) A ^ B b) A + B c) A ^ (- B) d)

^ is for AND, + is for OR , - is for NOT.
answer is c please check it.

5. in C "X ? Y : Z " is equal to
a) if (X==0) Y ;else Z
b) if (X!=0) Y ;else Z
c) if (X==0) Y ; Z
d)

6. foo()
int foo(int a, int b){
if (a&b) return 1;
return 0;
}

a) if either a or b are zero returns always 0
b) if both a & b are non zero returns always 1
c) if both a and b are negarive.......
d)

7. typedef struct nt{--------} node-type
node-type *p
a) p =( nodetype *)malloc( size of (node-type))
b)
c)
d)

8. function gives some error what changes as to be made
void ( int a,int b){
int t; t=a; a=b; b=t;
}
a)define void as int and write return tt
b)change everywhere a to *a and b to *b
c) d)

9. which of the following is incorrect
a) if a and b are defined as int arrays then (a==b) can never be
true
b) parameters are passed to functions only by values
c) defining functions in nested loops
d)

10. include
void swap(int*,int*);
main()
{
int arr[8]={36,8,97,0,161,164,3,9}
for (int i=0; i<7; i++)
for (int j=i+1; j<8;j++)
if(arr[i]}
void swap(int*x,int*y)
{
int temp; static int cnt=0;
temp= *x;
*x=*y;
*y=temp;
cnt++;
}

cnt = ?

a) 7 b) 15 c)1 d)

11. int main(){
FILE *fp;
fp=fopen("test.dat","w");
fprintf(fp,'hellon");
fclose(fp);
fp=fopen ("test.dat","w");
fprintf (fp, "world");
fclose(fp);
return 0;
}

if text.dat file is already present after compiling and execution
how many bytes does the file occupy

a) 0 bytes b)5 bytes c)11 bytes d)data is insufficient


12. f1(int*x,intflag)
int *y;
*y=*x+3;
switch(flag){
case 0:.........
....
........
break;
case 1:
*x=*y;
break;
case 2:
............
.......
.......
break;
}
return(*y)
main()
{
*x=5;
i=f1(x,0); j=f1(x,1);
printf("%.........",i,j,*x);
}

what is the output?
a) 8 8 8 b) 5 8 8 c) 8 5 8 d)


13. client server system (question about this i don't remember
exact question)


PART 2:
HERE A PROBLEM IS DEFINED YOU HAVE TO WRITE A PROGRAMME IN C OR C++

TWO SCHOOLS, HAVING DIFFERENT NO. OF CLASSES . EACH CLASS HAS
DIFFERENT NO. OF SECTIONS. THE 2 SCHOOLS HAVE TO BE MERGED
TOGETHER SO THAT A STUDENT OF SAME CLASS AND SECTION REMAIN
SAME. FOR EXAMPLE, 1A STUDENTS OF BOTH SCHOOLS SHOULD BE IN 1A
SECTION OF NEW SCHOOL

WRITE A PROGRAM FOR THE ABOVE USING
1) DYNAMIC MEMORY ALLOCATION
2) STRUCTURES

 

 




  
Total Answers and Comments: 1 Last Update: December 07, 2005   
  
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 Best Rated Answer

No best answer available. Please pick the good answer available or submit your answer.
December 07, 2005 03:20:42   #1  
sasidhar        

RE: I2 Technologies Placement...

for the 1st question answer is C(0.1111)

procedure

multiply .9375 with 2

.9375*2 1.8750 mark 1 which is left of the decimal point

and multiply .8750 with 2

.8750*2 1.7500

repeat as long as u can till u get zeros on the right of the decimal point


 
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 Related Questions

PLease post any I2 Technologies Placement Papers in the comments section.PART 1:THERE ARE 20 MULTIPLE CHOICE QUESTIONS .EACH QUESTION CARRIES 3MARKS.THERE IS NEGATIVE MARKING FOR EACH WRONG ANSWERMINUS 
Latest Answer : for the 1st question answer is C(0.1111)proceduremultiply .9375 with 2 .9375*2=1.8750 mark 1 which is left of the decimal pointand multiply .8750 with 2 .8750*2=1.7500repeat as long as u can till u get zeros on the right of the decimal point ...


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