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What is the most efficient way to count the number of bits which are set in a value?

  
Total Answers and Comments: 7 Last Update: May 30, 2008   
  
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July 20, 2005 12:20:29   #1  
Santosh        

RE: What is the most efficient way to count the number of bits which are set in a value?
shifting each bit left till the no of bits end
 
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September 06, 2005 04:55:36   #2  
Paresh        

RE: What is the most efficient way to count the number of bits which are set in a value?
foo(unsigned char *ByteField) 

int i=0,j=0; 
unsigned char *BytePos; 
short Bit; 
 
BytePos = ByteField + sizeof(ByteField); 
 
for (i=0; i
if (*(BytePos - i) > (char ) 0) 

for (j=0; j<8; j++) 

 
if (((*(BytePos - i)) & 1<
Bit = (i * 8) + j; 
printf("Bit Set %d n",Bit); 





 
Should give u the bit which are set

 
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October 21, 2005 07:10:41   #3  
Raks        

RE: What is the most efficient way to count the numbe...

#define ISBIT(pos,val) ((1<<(pos-1))&val)


void main(void)
{
 int i=0x00;
 int cnt=0;
 int pos=0;
 for(pos=1;pos<=(sizeof(i)*8);pos++)
 {
  if(ISBIT(pos,i))
  {
   cnt++;
  }
 }

 printf("Count %d",cnt);
}


 
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January 27, 2006 23:57:26   #4  
prakash        

RE: What is the most efficient way to count the numbe...

int cnt_bits(int num) {

   int cnt = 0;

   while(num) {

       if(num % 2) cnt++;

       num /= 2;

   }

   return cnt;

}


 
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August 17, 2006 23:58:22   #5  
ptusha        

RE: What is the most efficient way to count the numbe...

int fnCountbits(int num )
{
 int iCount = 0;
 while ( num )
 {
   num &= (num-1) ;
  iCount++;
 } 

return iCount;

}


 
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August 23, 2006 15:34:43   #6  
Visitor        

RE: What is the most efficient way to count the numbe...
Real smart solution to this question is to use a LookUp table.
 
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May 30, 2008 15:13:46   #7  
gunturi.prabhakar Member Since: May 2008   Contribution: 4    

RE: What is the most efficient way to count the number of bits which are set in a value?
is this auestion refers to how many bits are set to 1 in a value.
if that is the question then simply convert that value into bit code....
then you can get the answer easily.....

 
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