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 Aptitude  |  Question 107 of 124    Print  
In A, B, C are having some marbles with each of them. A has given B and C the same number of marbles each of them already have. Then, B gave C and A the same number of marbles they already have. Then C gave A and B the same number of marbles they already have. At the end A, B, and C have equal number of marbles. If x, y, z are the marbles initially with A, B, C respectively. If the total number of marbles are 72, then the number of marbles with A at the starting

A. 20
B. 30
C. 32
D. 39

D




  
Total Answers and Comments: 2 Last Update: March 14, 2007   
  
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December 23, 2005 04:21:14   #1  
Moulana Shareef        

RE: In A, B, C are having some marbles with each of th...

total no of marbles 72

at the end all are having equal no of marbles i.e. each having 24.

calculate from bottom:

A B C

39 21 12 (A gave 21 to B and 12 to C)

6 42 24 (B gave 6 to A and 12 to C)

12 12 48 ( c gave 12 to A and 12 to B)

24 24 24

ans:39


 
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March 14, 2007 09:26:31   #2  
swati shukla        

RE: In A, B, C are having some marbles with each of th...
Can be calculated by linear eqns. Where you get x+2y 87. Then x has a value such that y should be integral. Substitute the options. 39 is the right answer
 
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