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In A, B, C are having some marbles with each of them. A has given B and C the same number of marbles each of them already have. Then, B gave C and A the same number of marbles they already have. Then C gave A and B the same number of marbles they already have. At the end A, B, and C have equal number of marbles. If x, y, z are the marbles initially with A, B, C respectively. Then the number of marbles B have at the end

A. 2(x-y-z)
B. 4(x-y-z)
C. 2(3y-x-z)
D. x + y-z

C




  
Total Answers and Comments: 1 Last Update: October 28, 2005   
  
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October 28, 2005 14:57:49   #1  
JO        

RE: In A, B, C are having some marbles with each of th...

just follow the sentence

c.


 
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