RE: If a clock is 5% faster than a right clock then wh...
the answer is 4.77 it goes like thissuppose the right clock is R and the faster clock is Fthen acc to ques F R + R *5/100F R(105/100)R F(100/105)R F(.9523)thusR-F(1-.0477)thus R is 4.77 slower than F