Pipe A will fill the tank in 6hr and B in 4hr,if the pipes are opened alternatively, in which A is opened first, then how many hours it will take to fill the tank?

5 hours

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According to given data,First pipe(say x) will fill 1/6 of the tank in an hour.Second pipe(say y) will fill 1/4 of the tank in an hour.And therefore if both are opened alterativelyWe have an equatoin ( )x+( )y=1 ( )1/6+( )1/4=1To satisfy this we have in blanks 3 and 2 i.e,3+2=5Anwer is 5 hours.

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