Read the function conv() given below
conv(int t)
{
int u;
u=5/9 * (t-32);
return(u);
}
What is returned
A. 15
B. 0
C. 16.1
D. 29

This question is related to TCS Interview

Asked by: Interview Candidate | Asked on: Jun 6th, 2005

Return back to C

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Showing Answers 1 - 4 of 4 Answers

Pallavi

Answered On : Jun 6th, 2006

0 will be returned, because division of two integers (5/9) is 0.

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SUVI_1990

Answered On : Jun 13th, 2009

View all answers by SUVI_1990

0 is the answer
The division of 5/9 is 0.5
Then 0.5*(t-32) is -31.5
So roundup of this is 0.

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rajesh

Answered On : Aug 5th, 2011

absolutely its 0... coz u is declared as int.. so u=0.5.. so it take u as 0.. and anything*0 becomes zero..

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bhanupriya

Answered On : Jan 17th, 2012

Ans. is B. 0


Code
conv(int t){ int u; u=5/9 * (t-32); return(u); }

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Read the function conv() given below
conv(int t)
{
int u;
u=5/9 * (t-32);
return(u);
}
What is returned
A. 15
B. 0
C. 16.1
D. 29

Give your answer:

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