answer is 7.

1024*8+64*3+3=8387

8387 binary equivalent is 11100000110011

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**dhanasekaran**
Answered On : Dec 6th, 2005

the binary eqhivalent of 8387 is as follows10000011000011

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**Atul Dongare**
Answered On : Apr 17th, 2006

I think answer= 4 1's

it is because when we convert 8387 into binary then ans will be 10100011

so the no. of ones are 4

ans is 4

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**Parag**
Answered On : Apr 19th, 2006

Due to weight of each bit we have;8=1 one in binary form1024=1 one ie for 2 raise to 10 th position 3=2 ones and there are 2 threes in expression therefore 4 ones64=1 one means total 7 ones.Why to convert to binary unnneccesarily?

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5

because 8*1024+3*64+3=8387

binary equivalent of 8387 is 10000011000011

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the answer is 5bcoz if u covert 8387 into binary u will get 10000011000011so it has five onestherefore the solution is 5

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There are 5 ones in because 8*1024 + 3*64 + 3 = 8387

and its equivalant binary 10000011000011

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i am impressed by the imagination of parag to prove that no opf ones will be 7.

great imagination dude.

but answer is 5

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8*1024 + 64*3 + 3 = 8387

8387/2 then remainder = 1

4193/2 then remainder = 1

2096/2 then remainder = 0

1048/2 then remainder = 0

524/2 then remainder = 0

262/2 then remainder = 0

131/2 then remainder = 1

65/2 then remainder = 1

32/2 then remainder = 0

16/2 then remainder = 0

8/2 then remainder = 0

4/2 then remainder = 0

2/2 then remainder = 0

1/2=0 then remainder = 1

8387= 10000011000011

so overall we have 5 1's

Thank you

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ans 5

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ANS is 5.

8387/2=4193 Remainder 1

4193/2=2096 1

2096/2=1048 0

1048/2=524 0

524/2=262 0

262/2=131 0

131/2=65 1

65/2=32 0

32/2=16 0

16/2=8 0

8/2=4 0

4/2=2 0

2/2=1 0

1 1

so the binary code is 10000011000011

So Total no. of 1's =5

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8*1024 + 3*64 + 3= (2^3*2^10) + (2^1+2^0)*2^6 + (2^1+2^0)

= 2^13 + 2^7 +2^6 + 2^1 + 2^0

Hence 5

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