# How many 1's are there in the binary form of  8*1024 + 3*64 + 3

4

#### srikanth37 Profile Answers by srikanth37

• Dec 1st, 2005

1024*8+64*3+3=8387

8387  binary equivalent is 11100000110011

#### dhanasekaran

• Dec 6th, 2005

the binary eqhivalent of 8387 is as follows10000011000011

#### Atul Dongare

• Apr 17th, 2006

it is because when we convert 8387 into binary then ans will be 10100011

so the no. of ones are 4

ans is 4

#### Parag

• Apr 19th, 2006

Due to weight of each bit we have;8=1 one in binary form1024=1 one ie for 2 raise to 10 th position 3=2 ones and there are 2 threes in expression therefore 4 ones64=1 one means total 7 ones.Why to convert to binary unnneccesarily?

#### burogini.vinod Profile Answers by burogini.vinod

• Jan 20th, 2007

5

because 8*1024+3*64+3=8387

binary equivalent of 8387 is 10000011000011

#### karikolraj.b Profile Answers by karikolraj.b

• Jan 29th, 2007

the answer is 5bcoz if u covert 8387 into binary u will get 10000011000011so it has five onestherefore the solution is 5

#### jaymrms Profile Answers by jaymrms

• Jan 26th, 2008

There are 5 ones in because 8*1024 + 3*64 + 3 = 8387
and its  equivalant  binary 10000011000011

#### rajat17111985 Profile Answers by rajat17111985

• Feb 1st, 2008

i am impressed by the imagination of parag to prove that no opf ones will be 7.
great imagination dude.

#### Priyanka Sinha Profile Answers by Priyanka Sinha

• Mar 14th, 2008

8*1024 + 64*3 + 3 = 8387
8387/2 then remainder = 1
4193/2 then remainder = 1
2096/2 then remainder = 0
1048/2 then remainder = 0
524/2 then remainder = 0
262/2 then remainder = 0
131/2 then remainder = 1
65/2 then remainder = 1
32/2 then remainder = 0
16/2 then remainder = 0
8/2 then remainder = 0
4/2 then remainder = 0
2/2 then remainder = 0
1/2=0 then remainder = 1

8387= 10000011000011

so overall we have 5 1's
Thank you

#### chavan.shrikant1 Profile Answers by chavan.shrikant1

• Jun 22nd, 2008

ans 5

#### poonammusale Profile Answers by poonammusale

• Apr 22nd, 2009

ANS is 5.
8387/2=4193              Remainder 1
4193/2=2096                 1
2096/2=1048                 0
1048/2=524                   0
524/2=262                     0
262/2=131                     0
131/2=65                       1
65/2=32                         0
32/2=16                         0
16/2=8                           0
8/2=4                             0
4/2=2                             0
2/2=1                             0
1                                    1
so the binary code is 10000011000011
So Total no. of 1's =5

#### ashok815 Profile Answers by ashok815

• Dec 22nd, 2009

8*1024 + 3*64 + 3= (2^3*2^10) + (2^1+2^0)*2^6 + (2^1+2^0)

= 2^13 + 2^7 +2^6 + 2^1 + 2^0

Hence 5