Implement the logic equation Y = C^BA^ + CB^A + CBA with a multiplexer. (C^ = C complement )?

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Apr 10th, 2005
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Danny John

Aug 8th, 2006

Since Y=C'BA'+CB'A+CBA on simplification yields Y=C'BA' + CANow it depends on the multiplexer we are using. If 8:1 MUX is used then just use A, B, C as select lines and the output of the truth table as the 8 inputs of MUX.Now we can implement the same using 4:1MUX and 2:1 MUX using K-map. But I wont be able to show them. So by using K-maps and 4:1 MUX we can use B and C as select lines and the inputs are I0= 0, I1=A, I2=1, I3=0