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Question:  Two coins one with HEAD IN BOTH SIDES and the other coin HEAD IN ONE SIDE AND TAIL IN THE OTHER SIDE is in a box,a coin is taken at random and FOUND HEAD IN ONE SIDE .what is the probability that THE OTHER SIDE IS HEAD?

Answer: please answer this questions guys :::::::

1.Two coins one with HEAD IN BOTH SIDES and the other coin HEAD IN ONE SIDE AND TAIL IN THE
OTHER SIDE is in a box,a coin is taken at random and FOUND HEAD IN ONE SIDE .what is the
probability that THE OTHER SIDE IS HEAD?

2.12 Blacksox and 12 Whitesox mixed in a box,a pair of sox is picked at a time,in which pick/
how many pick ,to get the right pair(black&black or white&white)?

3.16 litre can, 7 litre can,3 litre can,the customer has to be given 11 litres of milk using
all the three cans only explain?

THANKS A LOT !!!


June 06, 2008 22:11:20 #8
 sravan_reddy001   Member Since: November 2005    Total Comments: 8 

RE: Two coins one with HEAD IN BOTH SIDES and the other coin HEAD IN ONE SIDE AND TAIL IN THE OTHER SIDE is in a box,a coin is taken at random and FOUND HEAD IN ONE SIDE .what is the probability that THE OTHER SIDE IS HEAD?
 
1) The probability of selecting one coin is 1/2(which is already completed)
now.. The probability of having head on other side is (1/2) since only one coin has head. Therefore the prob. that head on other side is 1/2(second value from above explanation)


2) selecting 2 black ones is (no of ways) : 12c2

selecting 2 white ones is :12c2

therefore, selecting a pair of particular color is 12c2+12c2 = 66+66 = 132

selecting 1 black & one white is : 12c1*12c1 == 144

Lets assume worst case (which is required)

since 144 is greater than 132. 

the first pick will be black & white, 2nd pick is also black & white ,3rd will be black or white, no of picks required : 3


3) use 7 lt can and pour milk in 16lt can, now take milk in 7lt can, take 3lt from that 7lt can, 7lt can will have 4 lts in it, pour that 4 lt in 16lt can, it has 7(previous)+4(later) in it...
     

 

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