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Question: 4.In two dimensional array X(7,9) each element occupies 2 bytes of memory.If the address of first element X(1,1)is 1258 then what will be the address of the element X(5,8) ?
whats the ans
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| April 04, 2008 22:19:55 |
#7 |
| imran4108 |
Member Since: April 2008 Total Comments: 1 |
RE: 4.In two dimensional array X(7,9) each element occupies 2 bytes of memory.If the address of first element X(1,1)is 1258 then what will be the address of the element X(5,8) ? whats the ans
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formulae is
X(5,8)=X(N,M)
X(7,9)=X(R,C)
X(5,8)=BASE+C*(M-1)*SIZE+(N-1)*SIZE
WHERE SIZE=2BYTES
BASE=1258
X(5,8)=1258+9*7*2+4*2 |
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