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GeekInterview.com > Placement Papers > Infosys > Analytical
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Question: Four Friends A, B, C and D are living in a hostel. One day A’s uncle came and gave him a box of laddoos, According to their rule whatever they get will be equally divided among them. So A divided the laddoos into four equal parts and he ate his part. Then B came to the room and he divided the laddoos into four equal parts and A and B ate their part. Then C came to the room he divided the laddoos into four equal parts and he ate his part. Then at the last D came to the room he also divided the laddoos into four equal parts and he ate his part. The number of laddoos D ate was 3.
1. How many laddoos did A eat?
2. How many laddoos did B eat?
3. How many laddoos did C eat?
4. How many laddoos were there in the box altogether?
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| March 03, 2008 05:52:19 |
#5 |
| vreswar |
Member Since: March 2008 Total Comments: 1 |
RE: Four Friends A, B, C and D are living in a hostel. One day A’s uncle came and gave him a box of laddoos, According to their rule whatever they get will be equally divided among them. So A divided the laddoos into four equal parts and he ate his part.
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Hi All,
My approach is quite simple:
Say there are x laddoes.
A shares x/4 each to himself, B,C,D. n eates it (A=x/4)
B comes and shares x/4*4 to each and eat (A=x/4+x/16, B=x/16)
C comes , shares x/4*4*4 to each and eat (A=x/4+x/16, B=x/16, c=x/64)
D comes, shares x/4*4*4*4 to each and eat (A=x/4+x/16, B=x/16, c=x/64, D=x/256)
as its given D eats 3: x/256 =3 => x=768 (Clear)
let us check it with c = x/64 => 768/64 = 12
B = x/16 =>768/16 = 48
A = x/4 + x/16 => 192+48 = 240
A=240, B=48,C=12 D=3.
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