Answer Detail: RE: could any one explan me what happens in this program. main(){ int i=10; i=(++i)/(i++); printf("i=%d",i); }

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Question: could any one explan me what happens in this program.

main(){
int i=10;
i=(++i)/(i++);
printf("i=%d",i);
}

February 02, 2008 01:13:14	#10
chethan HB	Testing Expert Member Since: November 2005 Total Comments: 2
RE: could any one explan me what happens in this program. main(){ int i=10; i=(++i)/(i++); printf("i=%d",i); }
1. i ++ will get execute so the value will be 10 . it wont increment. 2. ++i will be incremented to 11 3. 11/10 will result to 1 4.i=1 will get execute. 5. keep in mind still increment is not done.. this is done after exectuing , or ; 6. after executing i=1 ';' will be executed 7. i++ will get incremented to 2 so the answer is 2.