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GeekInterview.com > Placement Papers > Infosys > Analytical
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Question: Four Friends A, B, C and D are living in a hostel. One day A’s uncle came and gave him a box of laddoos, According to their rule whatever they get will be equally divided among them. So A divided the laddoos into four equal parts and he ate his part. Then B came to the room and he divided the laddoos into four equal parts and A and B ate their part. Then C came to the room he divided the laddoos into four equal parts and he ate his part. Then at the last D came to the room he also divided the laddoos into four equal parts and he ate his part. The number of laddoos D ate was 3.
1. How many laddoos did A eat?
2. How many laddoos did B eat?
3. How many laddoos did C eat?
4. How many laddoos were there in the box altogether?
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| December 12, 2007 12:20:42 |
#2 |
| vivekjain17 |
Member Since: December 2007 Total Comments: 3 |
RE: Four Friends A, B, C and D are living in a hostel. One day A’s uncle came and gave him a box of laddoos, According to their rule whatever they get will be equally divided among them. So A divided the laddoos into four equal parts and he ate his part.
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A eat 71 laddos
B eat 39 laddos
C eat 15 laddos
Total laddos were 128
Approach Since D eat 3 laddos that means when he came he saw there were 12 laddos (3*4)That means when C came in he must have seen 48 (12*4) laddos and divided then in four parts each which left 12 for D. Now important point to note here is that when C came he saw 48 laddos which were actually for C and D 24 each because if B has divided in 4 equal part he would have eat 24, give A as 24 and left 24 each for C and D. That gives us step that When B came in must have seen 96 (24*3) laddos. Which were actually for B, C and D. That gives us answer that when A got the box there should be 128 laddos which he divided in 4 equal parts of 32 each. So if we sum up laddos which A must have eat it will be (32+24+12+3) B (24+12+3) and C (12+3) and D we know it’s 3 |
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