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GeekInterview.com > Placement Papers > TCS > Aptitude
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Question: 4.In two dimensional array X(7,9) each element occupies 2 bytes of memory.If the address of first element X(1,1)is 1258 then what will be the address of the element X(5,8) ?
whats the ans
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| January 01, 2007 04:30:13 |
#6 |
| prashant kara |
Member Since: Visitor Total Comments: N/A |
RE: 4.In two dimensional array X(7,9) each element occ...
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| here, the address of first element x[1][1] is 1258 and also 2 byte of memory is given.now, we have to solve the address of element x[5][8], therefore, 1258+ 5*8*2 = 1258+80 = 1338 so the answer is 1338. |
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