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Question: Take this example:
#include
int main ()
{
int a [5];
a [3] = 1111;
printf ("3[a] = %dn", 3[a]);
return 0;
}
You notice that I use 3[a] instead of a[3], however, this code works fine but I don't know how.
It will be grateful if someone explians to me why and how this code works fine.
Thanks.
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| January 01, 2007 23:52:10 |
#3 |
| Bhushan |
Member Since: Visitor Total Comments: N/A |
RE: Take this example:#include
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regarding that printf statement.......... a[3] is internally calculated by compiler as (a+3). so 3[a] will be calculated as (3+a) . and these two statements calculates the same value and this is the reason why that code works. (Name of array itself acts as starting address of the array.) |
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