| September 09, 2006 16:09:53 |
#2 |
| Edwin Jose Palathinkal |
Member Since: Visitor Total Comments: N/A |
RE: there is 4 cube.They arrange in side by side.The b...
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| 1st cube:no of cubes painted on 1 sides = 4 cubes/face x 6 faces = 24 cubesno of cubes painted on 2 sides = 2 cubes/edge x 12 edges = 24 cubesno of cubes painted on 3 sides = 1 cube/vertex x 8 vertices = 8 cubes2nd cube:no of cubes painted on 1 sides = 1 cubes/face x 6 faces = 6 cubesno of cubes painted on 2 sides = 1 cubes/edge x 12 edges = 12 cubesno of cubes painted on 3 sides = 1 cube/vertex x 8 vertices = 8 cubes3rd cubeno of cubes painted on 1 sides = 1 cubes/face x 6 faces = 6 cubesno of cubes painted on 2 sides = 1 cubes/edge x 12 edges = 12 cubesno of cubes painted on 3 sides = 1 cube/vertex x 8 vertices = 8 cubestotal no of cubes painted on 1 sides = 24 + 6 + 6 = 36 cubestotal no of cubes painted on 2 sides = 24 + 12 + 12 = 48 cubestotal no of cubes painted on 3 sides = 8 + 8 + 8 = 24 cubes |
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