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Question: 1. In a two dimensional array X(9,7) with each element occupying 4 bytes of memory with the address of the first element x(1,1) is 3000,find the address of X(8,5) ? Ans is 3212 but how explain
2.194 base 10= ___ base 5
3.the base 5 representation of the decimal number 2048 is______
4.when 3/4 of a units digit is added to ten's digit of a two number,the sum of the digit becomes 10.If 1/4 of the ten's digit added to the unit's digit then the sum of the digits is 1 less than the previous.Find the number a)94 b)84 c)48 d)88
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| June 06, 2006 14:39:52 |
#1 |
| DeviRavikumar |
CRM Expert Member Since: June 2006 Total Comments: 1 |
RE: 1. In a two dimensional array X(9,7) with each ele...
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ans. X(1,1)=3000 (given) Each element occupies 4 bytes of memory so X(1,2)=3004 . . X(1,7)=3042 X(2,1)=3046 . X(2,7)=3052 X(3,1)=3056 ................X(3,7)=3080 X(4,1)=3084 .........X(4,7)=3108 X(5,1)=3112 .............X(5,7)=3136 X(6,1)=3140 ...............X(6,7)=3164 X(7,1)=3168 .................X(7,7)=3192 x(8,1)=3196 ...................X(8,5)=3212-----------ans |
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