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Question:  write a program in C to add five 32 bit numbers available at successive memory locations and to divide the result by sixth numer available at next successive location.

Answer: main()
{ long int i, sum=0,*p;
p=1001; /* assume the numbers are from 1001 location */
for (i=0;i<5;i++)
{ sum= sum+ *p ;
p=p+1;
}
sum=sum/(*p) ; /* use only /*(p) not /*p since it may come to comment */
printf (\


April 04, 2006 05:22:48 #1
 sivarajan   Member Since: Visitor    Total Comments: N/A 

RE: write a program in C to add five 32 bit numbers av...
 
#include int my_array[] = {1,23,-4,5,6,9}; // for example of a random arrayint *ptr ;int sum;long tot;int main(void){ int i; ptr = my_array; //since the name of the array is a pointer for(i=0; i<5; i++) { printf("\n the value of my_array[%d]is %d and is stored in %p ",i,my_array[i], (void *)&(my_array[i])); printf("\n ptr + %d = %d\t",i, *(ptr+i)); sum = sum + *(ptr++); printf("\nthe value of the sum is %d",sum); } tot = sum/(*ptr); printf("\nthe value of the total is %d\n",tot); return 0; }
     

 

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