| |
GeekInterview.com > Interview Questions > Programming > C
| Print | |
Question: main()
{
int i, j, *p;
i = 25;
j = 100;
p = &i; // Address of i is assigned to pointer p
printf("%f", i/(*p) ); // i is divided by pointer p
}
Answer: A) Compile error
B) 1.00000
C) Runtime error.
D) 0.00000
Explanation: Error because i/(*p) is 25/25 i.e 1 which is int & printed as a float, so abnormal program termination, runs if (float) i/(*p) -----> Type Casting. |
| January 01, 2006 03:52:30 |
#3 |
| Prasad.... |
Microsoft Expert Member Since: January 2006 Total Comments: 6 |
RE: main(){ int i, j, *p; i = 25;
|
It will mostly give run time error and not compile time error.... Also use typecasting i.e. use (float)i/(*p); and you will get 1.0000.. as the answer |
| |
Back To Question | |
