Latest Answer: #include#includevoid main(){int i,flag=0,k,l,m,n;char str[100];clrscr();printf("enter the string n");scanf("%s",str);l=strlen(str);printf("%d",l);l=l-1;i=0;while(strcmp(str[i],str[l])==0){if(i+1==l){printf("its ...
Latest Answer: Here is the code for finding the size of data types without using sizeof() #include#define size_of(data) ( (char *)(&data +1) - (char *)(&data))int main(){ int INT; char CHAR; ...
We have a 2 arrays e.g. arr1[]={2,3,4,4,5,6,7} , arr2[]={1,2,2,4,6,8,8} . Assuming that both the arrays We have a 2 arrays e.g. arr1[]={2,3,4,4,5,6,7} , arr2[]={1,2,2,4,6,8,8} . Assuming that both the arrays are sorted , if we want to write a program to find common numbers present in both arrays , how do we do that ? Note that nested for loop has a complexity of n2 , hence avoid nested for loop.
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